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Piping pressure sample calculation

Example 1 In the example on the right, claiming for plumbing loss.
  1. First, determine the equivalent length of straight plumbing pipe.
       1. Determine the full length of the pipe.
            (Full length)=3+4+2+10+5+6+2=32(m) since going and coming back is there
       2. Equivalent straight length of the tube joint is calculated using the chart.
            Screw type 90°Since short elbow`s 25 is1.6m(joint)=1.6×6=9.6(m)
       3.1, 2 total is calculated.
            64+9.6=73.6(m)
 2. Next, from flow rate and pipe diameter, hydraulic loss is determined.
From the graph, the intersection of 25A line and 30[ℓ/min] is 0.04
Multiply 3.1 and 2
73.6×0.04=2.944≒3(m) ※ In case of old steel pipe, it is 1.2~2.5 times.
       4. From Chiller to equipment, determine rise in the height.
            4+10=14(m)
Find the total of 5.3 and 4.
3+14=17(m)

 

capacity formula

 

Example 2 In the example on the right, claiming for plumbing grit loss.

 

capacity formula

 

  1. 8A

  2. 15A
  3. 20A
  4. 32A

1. First, determine the equivalent length of straight plumbing pipe. (Full length) = 2(m)
2. Next, from flow rate and pipe diameter, hydraulic loss is determined.
From the graph, the intersection is 30(ℓ/min) and each piping diameter is
    1. at 8A 8.4  
    2. at 15A 0.55
    3. at 20A  0.13
    4. at 32A  0.01
3. 1 and 2 multiply. *In case of old steel pipe etc., it is 1.2~2.5 times.
    1. at 8A  2×8.4=16.8(m)
    2. at 15A 2×0.55=1.1(m)
    3. at 20A 2×0.13=0.26(m)
    4. at 32A 2×0.01=0.02(m)
 

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